Talk:Code snippets

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Revision as of 20:28, 3 November 2007 by Chaecker (talk | contribs) (Make script accessible to Firebug)
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July 8 2007

Edit undone. 146.151.111.140, it looks like you deleted about 3 quarters of the page, so i undid your change. This does mean that you will have to make the intended changes again...

Restructure?

This page is rather messy. Does anyone have ideas for how to better structure this information? --Henrik 05:48, 5 June 2007 (EDT)

It is getting a bit big, perhaps separating it out into different pages, each with a short explanation, the code and some examples. The main page would just have the links and a one line description. Also some more logical categories could help. --Alien scum 18:43, 6 June 2007 (EDT)

array.forEach in XPath example

Re: http://wiki.greasespot.net/index.php?title=Code_Snippets&diff=prev&oldid=1784

Restored that example, it works fine (using Fx 2) without Prototype. See e.g. http://developer.mozilla.org/en/docs/Core_JavaScript_1.5_Reference:Objects:Array:forEach.

Just try it:

 // ==UserScript==
 // @name          Example
 // @namespace     wiki
 // @include       *
 // ==/UserScript==
 
 function $x(p, context) {
   if (!context) context = document;
   var i, arr = [], xpr = document.evaluate(p, context, null, XPathResult.UNORDERED_NODE_SNAPSHOT_TYPE, null);
   for (i = 0; item = xpr.snapshotItem(i); i++) arr.push(item);
   return arr;
 }
 
 var i, paragraphs = $x("//p");	 
 paragraphs.forEach(function(paragraph) { // Loop over every paragraph	 
 	paragraph.innerHTML = "Halloa!";	 
 });

--81.225.78.185 18:18, 25 March 2007 (EDT)

Make script accessible to Firebug

How does it work? How can I use this script?

Make script accessible to Firebug

How can I use this script and how does it work?