Talk:Code snippets: Difference between revisions
Alien scum (talk | contribs) |
No edit summary |
||
Line 1: | Line 1: | ||
== July 8 2007 == | |||
Edit undone. 146.151.111.140, it looks like you deleted about 3 quarters of the page, so i undid your change. This does mean that you will have to make the intended changes again... | |||
== Restructure? == | == Restructure? == | ||
Revision as of 02:43, 9 July 2007
July 8 2007
Edit undone. 146.151.111.140, it looks like you deleted about 3 quarters of the page, so i undid your change. This does mean that you will have to make the intended changes again...
Restructure?
This page is rather messy. Does anyone have ideas for how to better structure this information? --Henrik 05:48, 5 June 2007 (EDT)
It is getting a bit big, perhaps separating it out into different pages, each with a short explanation, the code and some examples. The main page would just have the links and a one line description. Also some more logical categories could help. --Alien scum 18:43, 6 June 2007 (EDT)
array.forEach in XPath example
Re: http://wiki.greasespot.net/index.php?title=Code_Snippets&diff=prev&oldid=1784
Restored that example, it works fine (using Fx 2) without Prototype. See e.g. http://developer.mozilla.org/en/docs/Core_JavaScript_1.5_Reference:Objects:Array:forEach.
Just try it:
// ==UserScript== // @name Example // @namespace wiki // @include * // ==/UserScript== function $x(p, context) { if (!context) context = document; var i, arr = [], xpr = document.evaluate(p, context, null, XPathResult.UNORDERED_NODE_SNAPSHOT_TYPE, null); for (i = 0; item = xpr.snapshotItem(i); i++) arr.push(item); return arr; } var i, paragraphs = $x("//p"); paragraphs.forEach(function(paragraph) { // Loop over every paragraph paragraph.innerHTML = "Halloa!"; });
--81.225.78.185 18:18, 25 March 2007 (EDT)